Last updated at Dec. 24, 2019 by Teachoo

Transcript

Ex 8.2, 3 If tan (A + B) = √3 and tan (A – B) = 1/√3 ; 0° < A + B ≤ 90°; A > B, find A and B. Given that Our equations are A + B = 60° …(1) A – B = 30° …(2) Adding (1) and (2) A + B + A – B = 60° + 30° 2A = 90° A = (90°)/2 A = 45° Putting A = "45°" in (1) A + B = 60° 45° + B = 60° B = 60° − 45° B = 15° Hence A = 45° , B = 15°

Ex 8.2

Ex 8.2, 1 (i)

Ex 8.2, 1 (ii)

Ex 8.2, 1 (iii)

Ex 8.2, 1 (iv) Important

Ex 8.2, 1 (v) Important

Ex 8.2, 2 (i) (MCQ)

Ex 8.2, 2 (ii) (MCQ)

Ex 8.2, 2 (iii) (MCQ) Important

Ex 8.2, 2 (iv) (MCQ)

Ex 8.2, 3 Important You are here

Ex 8.2, 4 (i) Important

Ex 8.2, 4 (ii) Important

Ex 8.2, 4 (iii)

Ex 8.2, 4 (iv)

Ex 8.2, 4 (v) Important

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.